Applying Type Lambdas with Scala

Type Lambda, a must-have when utilizing higher-kinded types with Scala programming language, is the topic of this post. In this post, we discuss the application of type lambda in solving specific problems.


In this section, we enumerate several concepts that are imperative to our today’s discussion.

Type Members

Scala allows defining type members in a trait or class as follows.

trait HList{
  type Hd

We can define an abstract type member Hd and we can also give a concrete meaning to Hd from its enclosing context, as shown next.

class IntList extends HList {
  type Hd = Int

As noted in #1, the above definition of Hd can also be used as an alias for type Int. For instance, we can define a type alias for Map[Int, V] asIntMap`–

type IntMap[V] = Map[Int, V]

Note that, in the above code, V is a parametric type parameter and can vary based on the context of IntMap.

Type Projection

We can access the type members of a class or trait with the # operator (similar to . operator in case of value members), e.g., IntList#Hd. For instance, the following line asserts that IntList#Hd is indeed an Int type.

implicitly[Int =:= IntList#Hd]

Type members of a class or a trait can be reused into different context and the relevant type checks are performed statically —

val x: IntList#Hd = 10

Design Principle

From the design perspective, type members are particularly interesting when they are evolved along with their enclosing type to match the behavior accordingly. As noted in #2, it is regarded as family polymorphism or covariant specialization.

Application of Type Lambda

Type Lambda is often regarded as Type-Level Lambda. As its name suggests, it is similar to anonymous functions, but for types. In fact, type lambdas are used to define an anonymous/inner types for a given context. It is particularly useful when a type constructor has fewer type parameters compared to the parameterized type that we want to apply in that context.

Next, we explain the concept of type lambda with an example.

Problem Description

Consider the following excellent example of a Functor from #2:

trait Functor[A, +M[_]]{
  def map[B] (f: A => B): M[B]

Notice that M[_] type constructor only accepts one type parameter. So, it is quite straightforward if we want extend the Functor defined above with a Seq types.

case class SeqFunctor[A](seq: Seq[A])
  extends Functor[A, Seq]{

  override def map[B](f: (A) => B): Seq[B] =

And we can use SeqFunctor as follows:

> val lst = List(1,2,3)
> ListFunctor(lst).map(_ * 10)
// prints List(10, 20, 30)

However, in case of Map[K, V], it would be tricky to extend, since Map[K,V] has two type parameters while M[_] type constructor only accepts one.


To solve this, we apply type lambda, which handles the additional type parameter as shown below.

case class MapFunctor[K,V](mapKV: Map[K,V])
  extends Functor[V, ({type L[a] = Map[K,a]})#L]{

  override def map[V2](f: V => V2): Map[K, V2] =
    mapKV map{
      case (k,v) => (k, f(v))

> MapFunctor(Map(1->1, 2->2, 3->3)).map(_ * 10)
// Result: Map(1 -> 10, 2 -> 20, 3 -> 30)

Here, we simply apply f on the values of mapKV. Thus, type variable are indeedV and V2.

Informally, we extend Functor for Map with a type lambda as follows–

Functor[A, +M[_]] ==>
    {type L[a] = Map[K, a]} // structural type definition
  #L // type projection

Here {type L[a] = Map[K, a]} denotes a structural type. It essentially specifies an inner/annonymous type alias L[a], which is then matched against the (outer) #L. Type parameter K is partially applied and has been resolved from the context in this case. By applying type projection, #L, we get the type member out of the structural type, and thus define an alias for Map[K,_] in effect.

As noted in #3, an empty block in the type position (as in M[_]) essentially creates an anonymous structural type and the type projection allows us to get the type member from it.

Additional Tricks

Type lambda seems a bit intimidating; and handling multiple of them leads to somewhat difficult-to-comprehend code. To avoid that, Dan Rosen proposed a trick.

To demonstrate that, lets consider the previous example. Revisiting the type lambda from MapFunctor, we note that the only varying type is V and V2. We can define a Functor for Map by avoiding type lambda and use type member Map[K] as shown below.

case class ReadableMapFunctor[K,V](mapKV: Map[K,V]){
  def mapFunctor[V2] = {
    type `Map[K]`[V2] = Map[K, V2]
    new Functor[V, `Map[K]`] {
      override def map[V2](f: (V) => V2): `Map[K]`[V2] = mapKV map{
        case (k,v) => (k, f(v))

> ReadableMapFunctor(Map(1->1, 2->2, 3->3))*10)
//Map(1 -> 10, 2 -> 20, 3 -> 30)

This trick handles the extra type parameter of Map[K, V]. Also note the backticks; they permit the use of [] in the name of an identifier #4.

Following gist (#5) outlines code examples used in this post.


Overall, it seems to be an excellent feature with specific use-case, yet quite verbose. Sometimes, it is quite difficult to head around it. But surely, it has its applications and is a nice-to-have tool for Scala developers.

Let me know if you have any question. Thanks for visiting this post and going through this rambling.


  1. Programming in Scala by Odersky et al.
  2. Programming Scala by Dean Wampler and Alex Payne.
  3. Stackoverflow answer by Kris Nuttycombe regaring the benefits of Type Lambda in Scala.
  4. A More Readable Type Lambda Trick by Dan Rosen
  5. Gist outlining the code

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